(8y-12)=-20y+30

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Solution for (8y-12)=-20y+30 equation: 



(8y-12)=-20y+30

We move all terms to the left:

(8y-12)-(-20y+30)=0

We get rid of parentheses

8y+20y-12-30=0

We add all the numbers together, and all the variables

28y-42=0

We move all terms containing y to the left, all other terms to the right

28y=42

y=42/28

y=1+1/2

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