(8y-3)/3y=2

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Solution for (8y-3)/3y=2 equation:



(8y-3)/3y=2
We move all terms to the left:
(8y-3)/3y-(2)=0
Domain of the equation: 3y!=0
y!=0/3
y!=0
y∈R
We multiply all the terms by the denominator
(8y-3)-2*3y=0
Wy multiply elements
(8y-3)-6y=0
We get rid of parentheses
8y-6y-3=0
We add all the numbers together, and all the variables
2y-3=0
We move all terms containing y to the left, all other terms to the right
2y=3
y=3/2
y=1+1/2

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