(8y-3)=(6y+17)

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Solution for (8y-3)=(6y+17) equation: 



(8y-3)=(6y+17)

We move all terms to the left:

(8y-3)-((6y+17))=0

We get rid of parentheses

8y-((6y+17))-3=0



We calculate terms in parentheses: -((6y+17)), so:

(6y+17)

We get rid of parentheses

6y+17

Back to the equation:

-(6y+17)



We get rid of parentheses

8y-6y-17-3=0

We add all the numbers together, and all the variables

2y-20=0

We move all terms containing y to the left, all other terms to the right

2y=20

y=20/2

y=10

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