(8y-4)=(4y+28)

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Solution for (8y-4)=(4y+28) equation: 



(8y-4)=(4y+28)

We move all terms to the left:

(8y-4)-((4y+28))=0

We get rid of parentheses

8y-((4y+28))-4=0



We calculate terms in parentheses: -((4y+28)), so:

(4y+28)

We get rid of parentheses

4y+28

Back to the equation:

-(4y+28)



We get rid of parentheses

8y-4y-28-4=0

We add all the numbers together, and all the variables

4y-32=0

We move all terms containing y to the left, all other terms to the right

4y=32

y=32/4

y=8

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