(8y-4)=(7y+3)

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Solution for (8y-4)=(7y+3) equation: 



(8y-4)=(7y+3)

We move all terms to the left:

(8y-4)-((7y+3))=0

We get rid of parentheses

8y-((7y+3))-4=0



We calculate terms in parentheses: -((7y+3)), so:

(7y+3)

We get rid of parentheses

7y+3

Back to the equation:

-(7y+3)



We get rid of parentheses

8y-7y-3-4=0

We add all the numbers together, and all the variables

y-7=0

We move all terms containing y to the left, all other terms to the right

y=7

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