(9(1-r))+(9(1-r))r=5

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Solution for (9(1-r))+(9(1-r))r=5 equation: 



(9(1-r))+(9(1-r))r=5

We move all terms to the left:

(9(1-r))+(9(1-r))r-(5)=0

We add all the numbers together, and all the variables

(9(-1r+1))+(9(-1r+1))r-5=0



We calculate terms in parentheses: +(9(-1r+1)), so:

9(-1r+1)

We multiply parentheses

-9r+9

Back to the equation:

+(-9r+9)



We get rid of parentheses

-9r+(9(-1r+1))r+9-5=0

We add all the numbers together, and all the variables

-9r+(9(-1r+1))r+4=0

We move all terms containing r to the left, all other terms to the right

-9r+(9(-1r+1))r=-4

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