(9)(10)=(x-3)(x+6)

Solution for (9)(10)=(x-3)(x+6) equation:

(9)(10)=(x-3)(x+6)

We move all terms to the left:

(9)(10)-((x-3)(x+6))=0

We multiply parentheses ..

-((+x^2+6x-3x-18))+910=0


We calculate terms in parentheses: -((+x^2+6x-3x-18)), so:

(+x^2+6x-3x-18)

We get rid of parentheses

x^2+6x-3x-18

We add all the numbers together, and all the variables

x^2+3x-18

Back to the equation:

-(x^2+3x-18)


We get rid of parentheses

-x^2-3x+18+910=0

We add all the numbers together, and all the variables

-1x^2-3x+928=0

a = -1; b = -3; c = +928;
Δ = b2-4ac
Δ = -32-4·(-1)·928
Δ = 3721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3721}=61$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-61}{2*-1}=\frac{-58}{-2}
=+29
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+61}{2*-1}=\frac{64}{-2}
=-32
$