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(9)/(4x)-(5)/(6)=(13)/(12x)
We move all terms to the left:
(9)/(4x)-(5)/(6)-((13)/(12x))=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 12x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
9/4x-(+13/12x)-5/6=0
We get rid of parentheses
9/4x-13/12x-5/6=0
We calculate fractions
(-240x^2)/1728x^2+3888x/1728x^2+(-1872x)/1728x^2=0
We multiply all the terms by the denominator
(-240x^2)+3888x+(-1872x)=0
We get rid of parentheses
-240x^2+3888x-1872x=0
We add all the numbers together, and all the variables
-240x^2+2016x=0
a = -240; b = 2016; c = 0;
Δ = b2-4ac
Δ = 20162-4·(-240)·0
Δ = 4064256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4064256}=2016$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2016)-2016}{2*-240}=\frac{-4032}{-480} =8+2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2016)+2016}{2*-240}=\frac{0}{-480} =0 $
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