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(9)/(x)=(3)/(2x)+30
We move all terms to the left:
(9)/(x)-((3)/(2x)+30)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x+30)!=0We get rid of parentheses
x∈R
9/x-3/2x-30=0
We calculate fractions
18x/2x^2+(-3x)/2x^2-30=0
We multiply all the terms by the denominator
18x+(-3x)-30*2x^2=0
Wy multiply elements
-60x^2+18x+(-3x)=0
We get rid of parentheses
-60x^2+18x-3x=0
We add all the numbers together, and all the variables
-60x^2+15x=0
a = -60; b = 15; c = 0;
Δ = b2-4ac
Δ = 152-4·(-60)·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15}{2*-60}=\frac{-30}{-120} =1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15}{2*-60}=\frac{0}{-120} =0 $
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