(9*9)+(r*r)=(r+6)(r+6)

Solution for (9*9)+(r*r)=(r+6)(r+6) equation:

(9*9)+(r*r)=(r+6)(r+6)

We move all terms to the left:

(9*9)+(r*r)-((r+6)(r+6))=0

We add all the numbers together, and all the variables

(+r*r)-((r+6)(r+6))+81=0

We get rid of parentheses

r*r-((r+6)(r+6))+81=0

We multiply parentheses ..

-((+r^2+6r+6r+36))+r*r+81=0


We calculate terms in parentheses: -((+r^2+6r+6r+36)), so:

(+r^2+6r+6r+36)

We get rid of parentheses

r^2+6r+6r+36

We add all the numbers together, and all the variables

r^2+12r+36

Back to the equation:

-(r^2+12r+36)


Wy multiply elements

r^2-(r^2+12r+36)+81=0

We get rid of parentheses

r^2-r^2-12r-36+81=0

We add all the numbers together, and all the variables

-12r+45=0

We move all terms containing r to the left, all other terms to the right

-12r=-45

r=-45/-12

r=3+3/4