(9+2i)+(3-i)=0

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Solution for (9+2i)+(3-i)=0 equation:


Simplifying
(9 + 2i) + (3 + -1i) = 0

Remove parenthesis around (9 + 2i)
9 + 2i + (3 + -1i) = 0

Remove parenthesis around (3 + -1i)
9 + 2i + 3 + -1i = 0

Reorder the terms:
9 + 3 + 2i + -1i = 0

Combine like terms: 9 + 3 = 12
12 + 2i + -1i = 0

Combine like terms: 2i + -1i = 1i
12 + 1i = 0

Solving
12 + 1i = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + 1i = 0 + -12

Combine like terms: 12 + -12 = 0
0 + 1i = 0 + -12
1i = 0 + -12

Combine like terms: 0 + -12 = -12
1i = -12

Divide each side by '1'.
i = -12

Simplifying
i = -12

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