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(9+2x)(8+2x)=210
We move all terms to the left:
(9+2x)(8+2x)-(210)=0
We add all the numbers together, and all the variables
(2x+9)(2x+8)-210=0
We multiply parentheses ..
(+4x^2+16x+18x+72)-210=0
We get rid of parentheses
4x^2+16x+18x+72-210=0
We add all the numbers together, and all the variables
4x^2+34x-138=0
a = 4; b = 34; c = -138;
Δ = b2-4ac
Δ = 342-4·4·(-138)
Δ = 3364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3364}=58$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-58}{2*4}=\frac{-92}{8} =-11+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+58}{2*4}=\frac{24}{8} =3 $
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