(9+3x)+(2x-2)=67

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Solution for (9+3x)+(2x-2)=67 equation: 



(9+3x)+(2x-2)=67

We move all terms to the left:

(9+3x)+(2x-2)-(67)=0

We add all the numbers together, and all the variables

(3x+9)+(2x-2)-67=0

We get rid of parentheses

3x+2x+9-2-67=0

We add all the numbers together, and all the variables

5x-60=0

We move all terms containing x to the left, all other terms to the right

5x=60

x=60/5

x=12

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