(9+4i)(-7+11i)=0

Solution for (9+4i)(-7+11i)=0 equation:

(9+4i)(-7+11i)=0

We add all the numbers together, and all the variables

(4i+9)(11i-7)=0

We multiply parentheses ..

(+44i^2-28i+99i-63)=0

We get rid of parentheses

44i^2-28i+99i-63=0

We add all the numbers together, and all the variables

44i^2+71i-63=0

a = 44; b = 71; c = -63;
Δ = b2-4ac
Δ = 712-4·44·(-63)
Δ = 16129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16129}=127$
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(71)-127}{2*44}=\frac{-198}{88}
=-2+1/4
$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(71)+127}{2*44}=\frac{56}{88}
=7/11
$