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(9+v)(2v+3)=0
We add all the numbers together, and all the variables
(v+9)(2v+3)=0
We multiply parentheses ..
(+2v^2+3v+18v+27)=0
We get rid of parentheses
2v^2+3v+18v+27=0
We add all the numbers together, and all the variables
2v^2+21v+27=0
a = 2; b = 21; c = +27;
Δ = b2-4ac
Δ = 212-4·2·27
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-15}{2*2}=\frac{-36}{4} =-9 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+15}{2*2}=\frac{-6}{4} =-1+1/2 $
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