(9+v)(2v-1)=0

Solution for (9+v)(2v-1)=0 equation:

(9+v)(2v-1)=0

We add all the numbers together, and all the variables

(v+9)(2v-1)=0

We multiply parentheses ..

(+2v^2-1v+18v-9)=0

We get rid of parentheses

2v^2-1v+18v-9=0

We add all the numbers together, and all the variables

2v^2+17v-9=0

a = 2; b = 17; c = -9;
Δ = b2-4ac
Δ = 172-4·2·(-9)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-19}{2*2}=\frac{-36}{4}
=-9
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+19}{2*2}=\frac{2}{4}
=1/2
$