(9+v)(3v+7)=0

Solution for (9+v)(3v+7)=0 equation:

(9+v)(3v+7)=0

We add all the numbers together, and all the variables

(v+9)(3v+7)=0

We multiply parentheses ..

(+3v^2+7v+27v+63)=0

We get rid of parentheses

3v^2+7v+27v+63=0

We add all the numbers together, and all the variables

3v^2+34v+63=0

a = 3; b = 34; c = +63;
Δ = b2-4ac
Δ = 342-4·3·63
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-20}{2*3}=\frac{-54}{6}
=-9
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+20}{2*3}=\frac{-14}{6}
=-2+1/3
$