(9+y)(3y+5)=0

Solution for (9+y)(3y+5)=0 equation:

(9+y)(3y+5)=0

We add all the numbers together, and all the variables

(y+9)(3y+5)=0

We multiply parentheses ..

(+3y^2+5y+27y+45)=0

We get rid of parentheses

3y^2+5y+27y+45=0

We add all the numbers together, and all the variables

3y^2+32y+45=0

a = 3; b = 32; c = +45;
Δ = b2-4ac
Δ = 322-4·3·45
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-22}{2*3}=\frac{-54}{6}
=-9
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+22}{2*3}=\frac{-10}{6}
=-1+2/3
$