(9-3/t)=(6+6/t)

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Solution for (9-3/t)=(6+6/t) equation: 



(9-3/t)=(6+6/t)

We move all terms to the left:

(9-3/t)-((6+6/t))=0



Domain of the equation: t)!=0

t!=0/1

t!=0

t∈R





Domain of the equation: t))!=0

t!=0/1

t!=0

t∈R



We add all the numbers together, and all the variables

(-3/t+9)-((6/t+6))=0

We get rid of parentheses

-3/t-((6/t+6))+9=0

We calculate fractions


(-3t)/t^2+(-((6*t)/t^2+9=0

We add all the numbers together, and all the variables

(-3t)/t^2+(-((+6t)/t^2+9=0

We calculate fractions

We do not support etpression: t^4

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