(9-3x)/3=-10x+21

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Solution for (9-3x)/3=-10x+21 equation:



(9-3x)/3=-10x+21
We move all terms to the left:
(9-3x)/3-(-10x+21)=0
We add all the numbers together, and all the variables
(-3x+9)/3-(-10x+21)=0
We get rid of parentheses
(-3x+9)/3+10x-21=0
We multiply all the terms by the denominator
(-3x+9)+10x*3-21*3=0
We add all the numbers together, and all the variables
(-3x+9)+10x*3-63=0
Wy multiply elements
(-3x+9)+30x-63=0
We get rid of parentheses
-3x+30x+9-63=0
We add all the numbers together, and all the variables
27x-54=0
We move all terms containing x to the left, all other terms to the right
27x=54
x=54/27
x=2

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