(9-3x)/4=(2x-4)/3

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Solution for (9-3x)/4=(2x-4)/3 equation: 



(9-3x)/4=(2x-4)/3

We move all terms to the left:

(9-3x)/4-((2x-4)/3)=0

We add all the numbers together, and all the variables

(-3x+9)/4-((2x-4)/3)=0

We calculate fractions


(-3x)/()+(-((2x-4)*4)/()=0



We calculate terms in parentheses: +(-((2x-4)*4)/(), so:

-((2x-4)*4)/(

We multiply all the terms by the denominator


-((2x-4)*4)



We calculate terms in parentheses: -((2x-4)*4), so:

(2x-4)*4

We multiply parentheses

8x-16

Back to the equation:

-(8x-16)



We get rid of parentheses

-8x+16

Back to the equation:

+(-8x+16)



We get rid of parentheses

(-3x)/()-8x+16=0

We multiply all the terms by the denominator


(-3x)-8x*()+16*()=0

We add all the numbers together, and all the variables

(-3x)-8x*()=0

We get rid of parentheses

-3x-8x*()=0

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