(9-v)/6=(-v+12)/3

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Solution for (9-v)/6=(-v+12)/3 equation: 



(9-v)/6=(-v+12)/3

We move all terms to the left:

(9-v)/6-((-v+12)/3)=0

We add all the numbers together, and all the variables

(-1v+9)/6-((-1v+12)/3)=0

We calculate fractions


(-v)/()+(-((-1v+12)*6)/()=0



We calculate terms in parentheses: +(-((-1v+12)*6)/(), so:

-((-1v+12)*6)/(

We multiply all the terms by the denominator


-((-1v+12)*6)



We calculate terms in parentheses: -((-1v+12)*6), so:

(-1v+12)*6

We multiply parentheses

-6v+72

Back to the equation:

-(-6v+72)



We get rid of parentheses

6v-72

Back to the equation:

+(6v-72)



We add all the numbers together, and all the variables

(-1v)/()+(6v-72)=0

We get rid of parentheses

(-1v)/()+6v-72=0

We multiply all the terms by the denominator


(-1v)+6v*()-72*()=0

We add all the numbers together, and all the variables

(-1v)+6v*()=0

We get rid of parentheses

-1v+6v*()=0

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