(9-x)(x+2)=0

Solution for (9-x)(x+2)=0 equation:

(9-x)(x+2)=0

We add all the numbers together, and all the variables

(-1x+9)(x+2)=0

We multiply parentheses ..

(-1x^2-2x+9x+18)=0

We get rid of parentheses

-1x^2-2x+9x+18=0

We add all the numbers together, and all the variables

-1x^2+7x+18=0

a = -1; b = 7; c = +18;
Δ = b2-4ac
Δ = 72-4·(-1)·18
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-11}{2*-1}=\frac{-18}{-2}
=+9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+11}{2*-1}=\frac{4}{-2}
=-2
$