(9/(x-3))=(3x/(x-3))

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Solution for (9/(x-3))=(3x/(x-3)) equation: 


D( x )

x-3 = 0

x-3 = 0

x-3 = 0

x-3 = 0 // + 3

x = 3

x in (-oo:3) U (3:+oo)

9/(x-3) = (3*x)/(x-3) // - (3*x)/(x-3)

9/(x-3)-((3*x)/(x-3)) = 0

9/(x-3)-3*x*(x-3)^-1 = 0

9/(x-3)+(-3*x)/(x-3) = 0

9-3*x = 0

(9-3*x)/(x-3) = 0

(9-3*x)/(x-3) = 0 // * x-3

9-3*x = 0

9-3*x = 0 // - 9

-3*x = -9 // : -3

x = -9/(-3)

x = 3

x in { 3} 

x belongs to the empty set

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