(9/10)*x=5400

Solution for (9/10)*x=5400 equation:

(9/10)*x=5400

We move all terms to the left:

(9/10)*x-(5400)=0


Domain of the equation: 10)*x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+9/10)*x-5400=0

We multiply parentheses

9x^2-5400=0

a = 9; b = 0; c = -5400;
Δ = b2-4ac
Δ = 02-4·9·(-5400)
Δ = 194400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{194400}=\sqrt{32400*6}=\sqrt{32400}*\sqrt{6}=180\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-180\sqrt{6}}{2*9}=\frac{0-180\sqrt{6}}{18}
=-\frac{180\sqrt{6}}{18}
=-10\sqrt{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+180\sqrt{6}}{2*9}=\frac{0+180\sqrt{6}}{18}
=\frac{180\sqrt{6}}{18}
=10\sqrt{6}
$