(9/10)g=7+(2/3)

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Solution for (9/10)g=7+(2/3) equation:



(9/10)g=7+(2/3)
We move all terms to the left:
(9/10)g-(7+(2/3))=0
Domain of the equation: 10)g!=0
g!=0/1
g!=0
g∈R
We add all the numbers together, and all the variables
(+9/10)g-(7+(+2/3))=0
We multiply parentheses
9g^2-(7+(+2/3))=0
We multiply all the terms by the denominator
9g^2*3))-(7+(+2=0
Wy multiply elements
27g^3+2=0
We do not support egpression: g^3

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