(9/10)g=7+(2/3)

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Solution for (9/10)g=7+(2/3) equation: 



(9/10)g=7+(2/3)

We move all terms to the left:

(9/10)g-(7+(2/3))=0



Domain of the equation: 10)g!=0

g!=0/1

g!=0

g∈R



We add all the numbers together, and all the variables

(+9/10)g-(7+(+2/3))=0

We multiply parentheses

9g^2-(7+(+2/3))=0

We multiply all the terms by the denominator


9g^2*3))-(7+(+2=0

Wy multiply elements

27g^3+2=0

We do not support egpression: g^3

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