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(9/10)z-2=(-19/20)z+3
We move all terms to the left:
(9/10)z-2-((-19/20)z+3)=0
Domain of the equation: 10)z!=0
z!=0/1
z!=0
z∈R
Domain of the equation: 20)z+3)!=0We add all the numbers together, and all the variables
z!=0/1
z!=0
z∈R
(+9/10)z-((-19/20)z+3)-2=0
We multiply parentheses
9z^2-((-19/20)z+3)-2=0
We multiply all the terms by the denominator
9z^2*20)z+3)-((-2*20)z+3)-19=0
We add all the numbers together, and all the variables
9z^2*20)z+3)-((-40)z+3)-19=0
Wy multiply elements
180z^3-40)z+3)-19=0
We do not support ezpression: z^3
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