(9/2z)+(4/5)=-2

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Solution for (9/2z)+(4/5)=-2 equation: 



(9/2z)+(4/5)=-2

We move all terms to the left:

(9/2z)+(4/5)-(-2)=0



Domain of the equation: 2z)!=0

z!=0/1

z!=0

z∈R



We add all the numbers together, and all the variables

(+9/2z)+(+4/5)-(-2)=0

We add all the numbers together, and all the variables

(+9/2z)+2+(+4/5)=0

We get rid of parentheses

9/2z+2+4/5=0

We calculate fractions

There is no solution for this equation

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