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(9/5)(3-x)=(3/4)(x-3)
We move all terms to the left:
(9/5)(3-x)-((3/4)(x-3))=0
Domain of the equation: 5)(3-x)!=0
x∈R
Domain of the equation: 4)(x-3))!=0We add all the numbers together, and all the variables
x∈R
(+9/5)(-1x+3)-((+3/4)(x-3))=0
We multiply parentheses ..
(-9x^2+9/5*3)-((+3/4)(x-3))=0
We calculate fractions
((-9x^2+9*4)(x-3)))/60x^2+()/60x^2=0
We can not solve this equation
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