(9/5)+(5m/4)=(8/20)

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Solution for (9/5)+(5m/4)=(8/20) equation: 



(9/5)+(5m/4)=(8/20)

We move all terms to the left:

(9/5)+(5m/4)-((8/20))=0

We add all the numbers together, and all the variables

(+5m/4)+(+9/5)-((+8/20))=0

We get rid of parentheses

5m/4+9/5-((+8/20))=0

We calculate fractions


1000m^2/()+()/()+()/()=0

We add all the numbers together, and all the variables

1000m^2/()+2=0

We multiply all the terms by the denominator


1000m^2+2*()=0

We add all the numbers together, and all the variables

1000m^2=0

a = 1000; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1000·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{2000}=0$

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