(9/5)c+32=F

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Solution for (9/5)c+32=F equation: 



(9/5)c+32=

We move all terms to the left:

(9/5)c+32-()=0



Domain of the equation: 5)c!=0

c!=0/1

c!=0

c∈R



We add all the numbers together, and all the variables

(+9/5)c+32-()=0

We add all the numbers together, and all the variables

(+9/5)c=0

We multiply parentheses

9c^2=0

a = 9; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·9·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$c=\frac{-b}{2a}=\frac{0}{18}=0$

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