(9/6x-9)=(x/2x-3)-1/3

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Solution for (9/6x-9)=(x/2x-3)-1/3 equation: 


x in (-oo:+oo)

(9/6)*x-9 = (x/2)*x-(1/3)-3 // - (x/2)*x-(1/3)-3

(9/6)*x-((x/2)*x)+1/3-9+3 = 0

(-1/2)*x^2+(9/6)*x+1/3-9+3 = 0

3/2*x-1/2*x^2-17/3 = 0

DELTA = (3/2)^2-(-17/3*(-1/2)*4)

DELTA = -109/12

DELTA < 0

x belongs to the empty set

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