(9/k)=(-3/20)

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Solution for (9/k)=(-3/20) equation:



(9/k)=(-3/20)
We move all terms to the left:
(9/k)-((-3/20))=0
Domain of the equation: k)!=0
k!=0/1
k!=0
k∈R
We add all the numbers together, and all the variables
(+9/k)-((-3/20))=0
We get rid of parentheses
9/k-((-3/20))=0
We calculate fractions
()/20k^2+(-((-3*k)/20k^2=0
We add all the numbers together, and all the variables
()/20k^2+(-((-3k)/20k^2=0
We multiply all the terms by the denominator
(-((-3k)+()=0
We calculate terms in parentheses: +(-((-3k)+(), so:
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We calculate terms in parentheses: +(-((-3k)+(), so:
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We calculate terms in parentheses: +(-((-3k)+(), so:
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We calculate terms in parentheses: +(-((-3k)+(), so:
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We calculate terms in parentheses: +(-((-3k)+(), so:
-((-3k)+(
We calculate terms in parentheses: +(-((-3k)+(), so:
-((-3k)+(
We calculate terms in parentheses: +(-((-3k)+(), so:
-((-3k)+(
We calculate terms in parentheses: +(-((-3k)+(), so:
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We calculate terms in parentheses: +(-((-3k)+(), so:
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We calculate terms in parentheses: +(-((-3k)+(), so:
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We calculate terms in parentheses: +(-((-3k)+(), so:
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We calculate terms in parentheses: +(-((-3k)+(), so:
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We calculate terms in parentheses: +(-((-3k)+(), so:
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