(9/x)+x=6

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Solution for (9/x)+x=6 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x+9/x = 6 // - 6

x+9/x-6 = 0

1*x^1+9*x^-1-6*x^0 = 0

(1*x^2-6*x^1+9*x^0)/(x^1) = 0 // * x^2

x^1*(1*x^2-6*x^1+9*x^0) = 0

x^1

x^2-6*x+9 = 0

x^2-6*x+9 = 0

DELTA = (-6)^2-(1*4*9)

DELTA = 0

x = 6/(1*2)

x = 3 or x = 3

x in { 3, 3} 

x in { 3, 3 }

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