(9/z)-(3/-z)

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Solution for (9/z)-(3/-z) equation: 


D( z )

-z = 0

z = 0

-z = 0

z = 0

z = 0

z = 0

z in (-oo:0) U (0:+oo)

9/z-(3/(-z)) = 0

9/z+3*z^-1 = 0

12*z^-1 = 0 // : 12

z^-1 = 0

z należy do O

z belongs to the empty set

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