(900+300x+25x2)=300+50x

Solution for (900+300x+25x2)=300+50x equation:

(900+300x+25x^2)=300+50x

We move all terms to the left:

(900+300x+25x^2)-(300+50x)=0

We add all the numbers together, and all the variables

(900+300x+25x^2)-(50x+300)=0

We get rid of parentheses

25x^2+300x-50x+900-300=0

We add all the numbers together, and all the variables

25x^2+250x+600=0

a = 25; b = 250; c = +600;
Δ = b2-4ac
Δ = 2502-4·25·600
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(250)-50}{2*25}=\frac{-300}{50}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(250)+50}{2*25}=\frac{-200}{50}
=-4
$