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(900+300x+25x^2)=300+50x
We move all terms to the left:
(900+300x+25x^2)-(300+50x)=0
We add all the numbers together, and all the variables
(900+300x+25x^2)-(50x+300)=0
We get rid of parentheses
25x^2+300x-50x+900-300=0
We add all the numbers together, and all the variables
25x^2+250x+600=0
a = 25; b = 250; c = +600;
Δ = b2-4ac
Δ = 2502-4·25·600
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(250)-50}{2*25}=\frac{-300}{50} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(250)+50}{2*25}=\frac{-200}{50} =-4 $
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