(99/100)x+x=1000

Solution for (99/100)x+x=1000 equation:

(99/100)x+x=1000

We move all terms to the left:

(99/100)x+x-(1000)=0


Domain of the equation: 100)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+99/100)x+x-1000=0

We add all the numbers together, and all the variables

x+(+99/100)x-1000=0

We multiply parentheses

99x^2+x-1000=0

a = 99; b = 1; c = -1000;
Δ = b2-4ac
Δ = 12-4·99·(-1000)
Δ = 396001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{396001}}{2*99}=\frac{-1-\sqrt{396001}}{198}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{396001}}{2*99}=\frac{-1+\sqrt{396001}}{198}
$