(9b-3)/(9)=(5b+5)/(3)

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Solution for (9b-3)/(9)=(5b+5)/(3) equation:



(9b-3)/(9)=(5b+5)/(3)
We move all terms to the left:
(9b-3)/(9)-((5b+5)/(3))=0
We calculate fractions
9b/()+(-((5b+5)*9)/()=0
We calculate terms in parentheses: +(-((5b+5)*9)/(), so:
-((5b+5)*9)/(
We multiply all the terms by the denominator
-((5b+5)*9)
We calculate terms in parentheses: -((5b+5)*9), so:
(5b+5)*9
We multiply parentheses
45b+45
Back to the equation:
-(45b+45)
We get rid of parentheses
-45b-45
Back to the equation:
+(-45b-45)
We get rid of parentheses
9b/()-45b-45=0
We multiply all the terms by the denominator
9b-45b*()-45*()=0
We add all the numbers together, and all the variables
9b-45b*()=0

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