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(9g+4)(7g+8)=0
We multiply parentheses ..
(+63g^2+72g+28g+32)=0
We get rid of parentheses
63g^2+72g+28g+32=0
We add all the numbers together, and all the variables
63g^2+100g+32=0
a = 63; b = 100; c = +32;
Δ = b2-4ac
Δ = 1002-4·63·32
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-44}{2*63}=\frac{-144}{126} =-1+1/7 $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+44}{2*63}=\frac{-56}{126} =-4/9 $
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