(9h+-5)-(4h+2);h=5

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Solution for (9h+-5)-(4h+2);h=5 equation: 



(9h+-5)-(4h+2)h=5

We move all terms to the left:

(9h+-5)-(4h+2)h-(5)=0

We add all the numbers together, and all the variables

(9h-5)-(4h+2)h-5=0

We multiply parentheses

-4h^2+(9h-5)-2h-5=0

We get rid of parentheses

-4h^2+9h-2h-5-5=0

We add all the numbers together, and all the variables

-4h^2+7h-10=0

a = -4; b = 7; c = -10;
Δ = b2-4ac
Δ = 72-4·(-4)·(-10)
Δ = -111
Delta is less than zero, so there is no solution for the equation

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