(9k-3)/9=(5k+5)/3

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Solution for (9k-3)/9=(5k+5)/3 equation: 



(9k-3)/9=(5k+5)/3

We move all terms to the left:

(9k-3)/9-((5k+5)/3)=0

We calculate fractions


9k/()+(-((5k+5)*9)/()=0



We calculate terms in parentheses: +(-((5k+5)*9)/(), so:

-((5k+5)*9)/(

We multiply all the terms by the denominator


-((5k+5)*9)



We calculate terms in parentheses: -((5k+5)*9), so:

(5k+5)*9

We multiply parentheses

45k+45

Back to the equation:

-(45k+45)



We get rid of parentheses

-45k-45

Back to the equation:

+(-45k-45)



We get rid of parentheses

9k/()-45k-45=0

We multiply all the terms by the denominator


9k-45k*()-45*()=0

We add all the numbers together, and all the variables

9k-45k*()=0

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