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(9m+8)(5m-2)=0
We multiply parentheses ..
(+45m^2-18m+40m-16)=0
We get rid of parentheses
45m^2-18m+40m-16=0
We add all the numbers together, and all the variables
45m^2+22m-16=0
a = 45; b = 22; c = -16;
Δ = b2-4ac
Δ = 222-4·45·(-16)
Δ = 3364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3364}=58$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-58}{2*45}=\frac{-80}{90} =-8/9 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+58}{2*45}=\frac{36}{90} =2/5 $
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