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(9p+8)(9p+7)=0
We multiply parentheses ..
(+81p^2+63p+72p+56)=0
We get rid of parentheses
81p^2+63p+72p+56=0
We add all the numbers together, and all the variables
81p^2+135p+56=0
a = 81; b = 135; c = +56;
Δ = b2-4ac
Δ = 1352-4·81·56
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(135)-9}{2*81}=\frac{-144}{162} =-8/9 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(135)+9}{2*81}=\frac{-126}{162} =-7/9 $
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