(9p-27)(5p=3)=0

Solution for (9p-27)(5p=3)=0 equation:

(9p-27)(5p=3)=0

We move all terms to the left:

(9p-27)(5p-(3))=0

We multiply parentheses ..

(+45p^2-27p-135p+81)=0

We get rid of parentheses

45p^2-27p-135p+81=0

We add all the numbers together, and all the variables

45p^2-162p+81=0

a = 45; b = -162; c = +81;
Δ = b2-4ac
Δ = -1622-4·45·81
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11664}=108$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-162)-108}{2*45}=\frac{54}{90}
=3/5
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-162)+108}{2*45}=\frac{270}{90}
=3
$