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(9t-6)/12-(8t+12)/12=2/3-t
We move all terms to the left:
(9t-6)/12-(8t+12)/12-(2/3-t)=0
Domain of the equation: 3-t)!=0We add all the numbers together, and all the variables
We move all terms containing t to the left, all other terms to the right
-t)!=-3
t!=-3/1
t!=-3
t∈R
(9t-6)/12-(8t+12)/12-(-1t+2/3)=0
We get rid of parentheses
(9t-6)/12-(8t+12)/12+1t-2/3=0
We calculate fractions
There is no solution for this equation
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