(9u-11)/2=(19u+11)/3

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Solution for (9u-11)/2=(19u+11)/3 equation: 



(9u-11)/2=(19u+11)/3

We move all terms to the left:

(9u-11)/2-((19u+11)/3)=0

We calculate fractions


9u/()+(-((19u+11)*2)/()=0



We calculate terms in parentheses: +(-((19u+11)*2)/(), so:

-((19u+11)*2)/(

We multiply all the terms by the denominator


-((19u+11)*2)



We calculate terms in parentheses: -((19u+11)*2), so:

(19u+11)*2

We multiply parentheses

38u+22

Back to the equation:

-(38u+22)



We get rid of parentheses

-38u-22

Back to the equation:

+(-38u-22)



We get rid of parentheses

9u/()-38u-22=0

We multiply all the terms by the denominator


9u-38u*()-22*()=0

We add all the numbers together, and all the variables

9u-38u*()=0

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