(9v-4)/3=(9v+4)/4+10

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Solution for (9v-4)/3=(9v+4)/4+10 equation: 



(9v-4)/3=(9v+4)/4+10

We move all terms to the left:

(9v-4)/3-((9v+4)/4+10)=0

We calculate fractions


(36v-16)/()+(-((9v+4)*3)/()=0



We calculate terms in parentheses: +(-((9v+4)*3)/(), so:

-((9v+4)*3)/(

We multiply all the terms by the denominator


-((9v+4)*3)



We calculate terms in parentheses: -((9v+4)*3), so:

(9v+4)*3

We multiply parentheses

27v+12

Back to the equation:

-(27v+12)



We get rid of parentheses

-27v-12

Back to the equation:

+(-27v-12)



We get rid of parentheses

(36v-16)/()-27v-12=0

We multiply all the terms by the denominator


(36v-16)-27v*()-12*()=0

We add all the numbers together, and all the variables

(36v-16)-27v*()=0

We get rid of parentheses

36v-27v*()-16=0

We move all terms containing v to the left, all other terms to the right

36v-27v*()=16

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