(9x)0.5(22-x)=0

Solution for (9x)0.5(22-x)=0 equation:

(9x)0.5(22-x)=0

We add all the numbers together, and all the variables

9x0.5(-1x+22)=0

We multiply parentheses

-9x^2+198x=0

a = -9; b = 198; c = 0;
Δ = b2-4ac
Δ = 1982-4·(-9)·0
Δ = 39204
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{39204}=198$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(198)-198}{2*-9}=\frac{-396}{-18}
=+22
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(198)+198}{2*-9}=\frac{0}{-18}
=0
$