(9x)=(3x+12)

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Solution for (9x)=(3x+12) equation:



(9x)=(3x+12)
We move all terms to the left:
(9x)-((3x+12))=0
We calculate terms in parentheses: -((3x+12)), so:
(3x+12)
We get rid of parentheses
3x+12
Back to the equation:
-(3x+12)
We get rid of parentheses
9x-3x-12=0
We add all the numbers together, and all the variables
6x-12=0
We move all terms containing x to the left, all other terms to the right
6x=12
x=12/6
x=2

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