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(9x+1)(5x-4)=0
We multiply parentheses ..
(+45x^2-36x+5x-4)=0
We get rid of parentheses
45x^2-36x+5x-4=0
We add all the numbers together, and all the variables
45x^2-31x-4=0
a = 45; b = -31; c = -4;
Δ = b2-4ac
Δ = -312-4·45·(-4)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-41}{2*45}=\frac{-10}{90} =-1/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+41}{2*45}=\frac{72}{90} =4/5 $
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